Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Review Exercises - Page 497: 9



Work Step by Step

We know that $\sqrt x^{2}=|x|$, because $|x|^{2}=x\times x=x^{2}$. Therefore, $-\sqrt x^{2}=-(|x|)=-|x|$. We must include the absolute value sign to ensure that the square root is positive, since we know that the square root of a real number cannot be negative.
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