Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 7 - Review Exercises - Page 497: 2

Answer

-17

Work Step by Step

We know that $\sqrt 289=17$, because $17^{2}=289$. Therefore, $-\sqrt 289=-(17)=-17$.
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