Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - 6.1 Exercises: 61

Answer

$-\frac{1}{2}$

Work Step by Step

$\frac{5k-10}{20-10k}=\frac{5(k-2)}{10(2-k)}=\frac{5(k-2)}{-10(k-2)}=-\frac{5}{10}\times\frac{k-2}{k-2}=-\frac{1}{2}\times1=-\frac{1}{2}$
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