Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 6 - Section 6.1 - Rational Expressions and Functions; Multiplying and Dividing - 6.1 Exercises - Page 375: 60

Answer

$-\frac{x+2}{x-2}$

Work Step by Step

$\frac{(8-p)(x+2)}{(p-8)(x-2)}=\frac{-(p-8)(x+2)}{(p-8)(x-2)}=-\frac{p-8}{p-8}\times\frac{x+2}{x-2}=-1\times\frac{x+2}{x-2}=-\frac{x+2}{x-2}$
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