## Intermediate Algebra (12th Edition)

Published by Pearson

# Chapter 5 - Section 5.2 - Factoring Trinomials - 5.2 Exercises - Page 337: 8

#### Answer

$(y+9)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ To factor the given expression, $y^2+11y+18 ,$ find two numbers, $m_1$ and $m_2,$ whose product is $c$ and whose sum is $b$ in the quadratic expression $x^2+bx+c.$ Then, express the factored form as $(x+m_1)(x+m_2).$ $\bf{\text{Solution Details:}}$ In the given expression, the value of $c$ is $18$ and the value of $b$ is $11 .$ The possible pairs of integers whose product is $c$ are \begin{array}{l}\require{cancel} \{ 1,18 \}, \{ 2,9 \}, \{ 3,6 \}, \{ -1,-18 \}, \{ -2,-9 \}, \{ -3,-6 \} .\end{array} Among these pairs, the one that gives a sum of $b$ is $\{ 2,9 \}.$ Hence, the factored form of the given expression is \begin{array}{l}\require{cancel} (y+2)(y+9) .\end{array} The missing factor in the given expression is $(y+9) .$

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