Answer
$(x+8)$
Work Step by Step
$\bf{\text{Solution Outline:}}$
To factor the given expression, $
x^2+4x-32
,$ find two numbers, $m_1$ and $m_2,$ whose product is $c$ and whose sum is $b$ in the quadratic expression $x^2+bx+c.$ Then, express the factored form as $(x+m_1)(x+m_2).$
$\bf{\text{Solution Details:}}$
In the given expression, the value of $c$ is $
-32
$ and the value of $b$ is $
4
.$
The possible pairs of integers whose product is $c$ are
\begin{array}{l}\require{cancel}
\{ 1,-32 \}, \{ 2,-16 \}, \{ 4,-8 \},
\{ -1,32 \}, \{ -2,16 \}, \{ -4,8 \}
.\end{array}
Among these pairs, the one that gives a sum of $b$ is $\{
-4,8
\}.$ Hence, the factored form of the given expression is
\begin{array}{l}\require{cancel}
(x-4)(x+8)
.\end{array}
The missing factor in the given expression is $
(x+8)
.$
