Answer
$(z-4)(z+6)$
Work Step by Step
$\bf{\text{Solution Outline:}}$
To factor the quadratic expression $x^2+bx+c,$ find two numbers, $m_1$ and $m_2,$ whose product is $c$ and whose sum is $b$. Then, express the factored form as $(x+m_1)(x+m_2).$
$\bf{\text{Solution Details:}}$
In the given expression, $
z^2+2z-24
,$ the value of $c$ is $
-24
$ and the value of $b$ is $
2
.$
The possible pairs of integers whose product is $c$ are
\begin{array}{l}\require{cancel}
\{ 1,-24 \}, \{ 2,-12 \}, \{ 3,-8 \}, \{ 4,-6 \},
\{ -1,24 \}, \{ -2,12 \}, \{ -3,8 \}, \{ -4,6 \}
.\end{array}
Among these pairs, the one that gives a sum of $b$ is $\{
-4,6
\}.$ Hence, the factored form of the given expression is
\begin{array}{l}\require{cancel}
(z-4)(z+6)
.\end{array}