Answer
$k=\dfrac{-2t-3s}{b-1}$
Work Step by Step
$\bf{\text{Solution Outline:}}$
To solve the given equation, $
3s+bk=k-2t
,$ for $
k
,$ put all expressions with $
k
$ on one side and all other expressions on the other side. Then use the properties of equality to isolate and solve for the variable.
$\bf{\text{Solution Details:}}$
Putting all variables with $k$ on the left side, the equation above is equivalent to
\begin{array}{l}\require{cancel}
bk-k=-2t-3s
.\end{array}
Factoring $k$ on the left side and using the properties of equality, the equation above is equivalent to
\begin{array}{l}\require{cancel}
k(b-1)=-2t-3s
\\\\
\dfrac{k(b-1)}{(b-1)}=\dfrac{-2t-3s}{(b-1)}
\\\\
k=\dfrac{-2t-3s}{b-1}
.\end{array}
