## Intermediate Algebra (12th Edition)

$x=\left\{ -\dfrac{2}{5},-1 \right\}$
$\bf{\text{Solution Outline:}}$ To solve the given eqution, $(5x+2)(x+1)=0 ,$ equate each factor to zero (Zero Product Property). Then solve each equation. $\bf{\text{Solution Details:}}$ Equating each factor to zero (Zero Product Property), the solutions to the equation above are \begin{array}{l}\require{cancel} 5x+2=0 \\\\\text{OR}\\\\ x+1=0 .\end{array} Solving each equation results to \begin{array}{l}\require{cancel} 5x+2=0 \\\\ 5x=-2 \\\\ x=-\dfrac{2}{5} \\\\\text{OR}\\\\ x+1=0 \\\\ x=-1 .\end{array} Hence, $x=\left\{ -\dfrac{2}{5},-1 \right\} .$