Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 5 - Review Exercises: 28

Answer

$(x+7)^2$

Work Step by Step

$\bf{\text{Solution Outline:}}$ To factor the given expression, $ x^2+14x+49 ,$ find two numbers, $m_1$ and $m_2,$ whose product is $c$ and whose sum is $b$ in the quadratic expression $x^2+bx+c.$ Then, express the factored form as $(x+m_1)(x+m_2).$ $\bf{\text{Solution Details:}}$ In the expression above, the value of $c$ is $ 49 $ and the value of $b$ is $ 14 .$ The possible pairs of integers whose product is $c$ are \begin{array}{l}\require{cancel} \{ 1,49 \}, \{ 7,7 \}, \\ \{ -1,-49 \}, \{ -7,-7 \} .\end{array} Among these pairs, the one that gives a sum of $b$ is $\{ 7,7 \}.$ Hence, the factored form of the expression above is \begin{array}{l}\require{cancel} (x+7)(x+7) \\\\= (x+7)^2 .\end{array}
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