Answer
$3y+4-\dfrac{5}{y}$
Work Step by Step
Dividing the denominator to each of the terms of the numerator, the given expression, $
\dfrac{9y^2+12y-15}{3y}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{9y^2}{3y}+\dfrac{12y}{3y}-\dfrac{15}{3y}
\\\\=
3y+4-\dfrac{5}{y}
.\end{array}
