Answer
$\dfrac{2b}{a}+\dfrac{5}{3}+\dfrac{3c}{a}$
Work Step by Step
Dividing the denominator to each of the terms of the numerator, the given expression, $
\dfrac{12ab^2c+10a^2bc+18abc^2}{6a^2bc}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{12ab^2c}{6a^2bc}+\dfrac{10a^2bc}{6a^2bc}+\dfrac{18abc^2}{6a^2bc}
\\\\=
\dfrac{2b}{a}+\dfrac{5}{3}+\dfrac{3c}{a}
.\end{array}
