## Intermediate Algebra (12th Edition)

$8-\dfrac{9}{x}+\dfrac{3}{2x^2}$
Dividing the denominator to each of the terms of the numerator, the given expression, $\dfrac{64x^3-72x^2+12x}{8x^3} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{64x^3}{8x^3}-\dfrac{72x^2}{8x^3}+\dfrac{12x}{8x^3} \\\\= 8-\dfrac{9}{x}+\dfrac{3}{2x^2} .\end{array}