Answer
$9t^2-12st+4s^2$
Work Step by Step
Using $(a+b)^2=a^2+2ab+b^2$ or the square of a binomial, the product of the given expression, $
(3t-2s)^2
,$ is
\begin{array}{l}\require{cancel}
(3t)^2+2(3t)(-2s)+(-2s)^2
\\\\=
9t^2-12st+4s^2
.\end{array}
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter 4 - Review Exercises - Page 318: 62
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