Answer
$3q^3-13q^2-14q+20$
Work Step by Step
Using the Distributive Property, the product of the given expression, $
(3q^2+2q-4)(q-5)
,$ is
\begin{array}{l}\require{cancel}
3q^2(q)+3q^2(-5)+2q(q)+2q(-5)-4(q)-4(-5)
\\\\=
3q^3-15q^2+2q^2-10q-4q+20
\\\\=
3q^3+(-15q^2+2q^2)+(-10q-4q)+20
\\\\=
3q^3-13q^2-14q+20
.\end{array}
