Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 4 - Review Exercises: 59

Answer

$3q^3-13q^2-14q+20$

Work Step by Step

Using the Distributive Property, the product of the given expression, $ (3q^2+2q-4)(q-5) ,$ is \begin{array}{l}\require{cancel} 3q^2(q)+3q^2(-5)+2q(q)+2q(-5)-4(q)-4(-5) \\\\= 3q^3-15q^2+2q^2-10q-4q+20 \\\\= 3q^3+(-15q^2+2q^2)+(-10q-4q)+20 \\\\= 3q^3-13q^2-14q+20 .\end{array}
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