Answer
$2x^3+22x^2+56x$
Work Step by Step
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method, the product of the binomials in the given expression, $
2x(x+4)(x+7)
,$ is
\begin{array}{l}\require{cancel}
2x[x(x)+x(7)+4(x)+4(7)]
\\\\=
2x[x^2+7x+4x+28]
\\\\=
2x[x^2+11x+28]
.\end{array}
Using $a(b+c)=ab+ac$ or the Distributive Property, the product of the expression above is
\begin{array}{l}\require{cancel}
2x(x^2)+2x(11x)+2x(28)
\\\\=
2x^3+22x^2+56x
.\end{array}
