## Intermediate Algebra (12th Edition)

$F=\{ (1960,0.76),(1980,2.69),(2000,5.39),(2013,8.38) \}$
$\bf{\text{Solution Outline:}}$ Use the function notation of ordered pairs which is given by \begin{array}{l}\require{cancel} F=\{ (x_1,y_1),(x_2,y_2),(x_3,y_3),... \} .\end{array} $\bf{\text{Solution Details:}}$ In terms of function, $F,$ the given table of values is equivalent to \begin{array}{l}\require{cancel} F=\{ (1960,0.76),(1980,2.69),(2000,5.39),(2013,8.38) \} .\end{array}