Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.5 - Introduction to Relations and Functions - 2.5 Exercises: 11

Answer

$F=\{ (A,4),(B,3),(C,2),(D,1),(F,0) \}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the function notation of ordered pairs which is given by \begin{array}{l}\require{cancel} F=\{ (x_1,y_1),(x_2,y_2),(x_3,y_3),... \} .\end{array} $\bf{\text{Solution Details:}}$ In terms of function, $F,$ the given table of values is equivalent to \begin{array}{l}\require{cancel} F=\{ (A,4),(B,3),(C,2),(D,1),(F,0) \} .\end{array}
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