Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 2 - Section 2.5 - Introduction to Relations and Functions - 2.5 Exercises: 7

Answer

$F=\{ (2,-2),(2,0),(2,1) \}$

Work Step by Step

In terms of function, $F,$ the given table of values is equivalent to \begin{array}{l}\require{cancel} F=\{ (2,-2),(2,0),(2,1) \} .\end{array}
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