Answer
Using the property of the dot product, we have
\begin{align*}
\frac{1}{4}\|{u}+{v}\|^{2}-\frac{1}{4}\|{u}-{v}\|^{2}&=\frac{1}{4}(u+v)\cdot (u+v)-\frac{1}{4}(u-v)\cdot (u-v)\\
&=\frac{1}{4}(u\cdot u+2u\cdot v+v\cdot v)\\
&-\frac{1}{4}(u\cdot u-2u\cdot v+v\cdot v)\\
&=-frac{1}{4}(4 u\cdot v)\\
&=u\cdot v.
\end{align*}
Work Step by Step
Using the property of the dot product, we have
\begin{align*}
\frac{1}{4}\|{u}+{v}\|^{2}-\frac{1}{4}\|{u}-{v}\|^{2}&=\frac{1}{4}(u+v)\cdot (u+v)-\frac{1}{4}(u-v)\cdot (u-v)\\
&=\frac{1}{4}(u\cdot u+2u\cdot v+v\cdot v)\\
&-\frac{1}{4}(u\cdot u-2u\cdot v+v\cdot v)\\
&=-frac{1}{4}(4 u\cdot v)\\
&=u\cdot v.
\end{align*}