Answer
$u\cdot (cv+dw)=0$.
Work Step by Step
Since $u$ is orthogonal to $v$ and $w$, then we get
$$u\cdot v=0, \quad u\cdot w=0.$$
Keeping this in mind, now,
\begin{align*}
u\cdot (cv+dw)&=c (u\cdot v)+d (u\cdot w)\\
&=0+0\\
&=0.
\end{align*}
Hence, $u$ is orthogonal to $cv+dw$.