Elementary Linear Algebra 7th Edition

Published by Cengage Learning

Chapter 5 - Inner Product Spaces - 5.1 Length and Dot Product in Rn - 5.1 Exercises - Page 236: 80

Answer

$\theta=\arccos \left(\frac{2}{\sqrt{6}}\right)$

Work Step by Step

The diagonal of a cube can be represented by the vector u=(1,1,1) and one of its sides can be represented by v=(1,1,0). Then, the angle between u and v is given by $\theta=\arccos \left(\frac{u \cdot v}{\|u\|\|v\|}\right)=\arccos \left(\frac{2}{\sqrt{6}}\right)$

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