## Elementary Linear Algebra 7th Edition

Published by Cengage Learning

# Chapter 4 - Vector Spaces - 4.3 Subspaces of Vector Spaces - 4.3 Exercises - Page 167: 9

#### Answer

$W$ is not a vector subspace of $R^2$.

#### Work Step by Step

Let $u=(1,2)\in W$, so the components of $u$ are rational but the vector $\sqrt{2}u=\sqrt{2}(1,2)=(\sqrt{2,2\sqrt{2}})$ has irrational components. Hence $W$ is not vector subspace of $R^2$.

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