$W$ is not a vector subspace of $R^2$.
Work Step by Step
Let $u=(2,8), v=(3,27)\in W$. Now, $$u+v=(2,8)+(3,27)=(5,35).$$ Since $35\neq 5^3$, then $u+v$ is not an element of $W$. Hence, $W$ is not a vector subspace of $R^2$.
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