## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$p=\dfrac{5}{6}$
Using the properties of equality, the value of the variable that satisfies the given expression, $-\dfrac{2}{3}+p=\dfrac{1}{6} ,$ is \begin{array}{l}\require{cancel} p=\dfrac{1}{6}+\dfrac{2}{3} \\\\ p=\dfrac{1}{6}+\dfrac{4}{6} \\\\ p=\dfrac{1+4}{6} \\\\ p=\dfrac{5}{6} .\end{array}