Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter R - Elementary Algebra Review - R.2 Equations, Inequalities, and Problem Solving - R.2 Exercise Set - Page 946: 22



Work Step by Step

Using the properties of equality, the value of the variable that satisfies the given expression, $ 1.8x+0.16=4.2-0.05x ,$ is \begin{array}{l}\require{cancel} 1.8x+0.05x=4.2-0.16 \\\\ 1.85x=4.04 \\\\ x=\dfrac{4.04}{1.85} \\\\ x=\dfrac{4.04}{1.85}\cdot\dfrac{100}{100} \\\\ x=\dfrac{404}{185} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.