## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x=\dfrac{404}{185}$
Using the properties of equality, the value of the variable that satisfies the given expression, $1.8x+0.16=4.2-0.05x ,$ is \begin{array}{l}\require{cancel} 1.8x+0.05x=4.2-0.16 \\\\ 1.85x=4.04 \\\\ x=\dfrac{4.04}{1.85} \\\\ x=\dfrac{4.04}{1.85}\cdot\dfrac{100}{100} \\\\ x=\dfrac{404}{185} .\end{array}