## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$t=-\dfrac{1}{12}$
Using the properties of equality, the value of the variable that satisfies the given expression, $t+\dfrac{1}{3}=\dfrac{1}{4} ,$ is \begin{array}{l}\require{cancel} t=\dfrac{1}{4}-\dfrac{1}{3} \\\\ t=\dfrac{3}{12}-\dfrac{4}{12} \\\\ t=\dfrac{3-4}{12} \\\\ t=\dfrac{-1}{12} \\\\ t=-\dfrac{1}{12} .\end{array}