## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$y=\frac{2}{5},\:x=2$$
We solve the equations using substitution: $$3\cdot \frac{8-5y}{3}-5y=4\\ \quad y=\frac{2}{5}\\ x=\frac{8-5\cdot \frac{2}{5}}{3} \\ x=2$$