Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - Mid-Chapter Review - Mixed Review - Page 540: 8



Work Step by Step

We solve the equations using substitution: $$ 3\cdot \frac{8-5y}{3}-5y=4\\ \quad y=\frac{2}{5}\\ x=\frac{8-5\cdot \frac{2}{5}}{3} \\ x=2$$
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