Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - Mid-Chapter Review - Mixed Review - Page 540: 11

Answer

$$y=1,\:x=1$$

Work Step by Step

We solve the system of equations using substitution: $$\frac{23}{10}\cdot \frac{8+3y}{11}+\frac{3}{10}y=\frac{13}{5}\\ y=1 \\ x=\frac{8+3\cdot \:1}{11} \\ x=1$$
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