Answer
$$z=-3,\:y=-10,\:x=2$$
Work Step by Step
Solving the system of equations using substitution, we find:
$$ \frac{-1-\left(-\frac{-14z+8}{5}\right)+z}{3}-\left(-\frac{-14z+8}{5}\right)+3z=3\\ z=-3 \\ y=-\frac{-14\left(-3\right)+8}{5}=-10 \\ x=\frac{-1-\left(-10\right)-3}{3}=2$$
