Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.4 Systems of Equations in Three Variables - 8.4 Exercise Set - Page 537: 9



Work Step by Step

Solving the system of equations using substitution, we find: $$ \begin{bmatrix}2\left(y+z\right)-3y+2z=7\\ -\left(y+z\right)+2y+z=1\end{bmatrix}\\ -\left(-7+4z+z\right)+2\left(-7+4z\right)+z=1\\ \\ z=2 \\ y=-7+4\cdot \:2\\ x=1+2 \\ z=2,\:y=1,\:x=3$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.