Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.4 Systems of Equations in Three Variables - 8.4 Exercise Set - Page 537: 16



Work Step by Step

Solving the system of equations using substitution, we find: $$ 7\cdot \frac{13+2\cdot \frac{25c-154}{26}-7c}{3}-9\cdot \frac{25c-154}{26}-9c=-3 \\ c=2 \\ b=\frac{25\cdot \:2-154}{26}=-4 \\ a=\frac{13+2\left(-4\right)-7\cdot \:2}{3}=-3 $$
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