Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$z=-1,\:y=5,\:x=-4$$
Solving the system of equations using substitution, we find: $$2\left(4-\left(-7z-2\right)+3z\right)-\left(-7z-2\right)+z=-14 \\ z=-1 \\ y=-7\left(-1\right)-2=5\\ x=4-5+3\left(-1\right)=-4$$