Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - Review Exercises: Chapter 5 - Page 370: 59


No solution

Work Step by Step

Subtracting 25 on both sides of the equation, we find: $$ x^2=-25$$ A number squared is always positive. Thus, it is impossible for $x^2$ to be equal to a negative number, so there is no solution.
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