## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$x=2,\:x=-3,\:x=\frac{5}{2}$$
Solving the equation by factoring, we obtain: $$0=\left(x-2\right)\cdot \:2x^2+x\left(x-2\right)-\left(x-2\right)\cdot \:15 \\ \left(x-2\right)\left(x+3\right)\left(2x-5\right)=0 \\ x=2,\:x=-3,\:x=\frac{5}{2}$$