Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - Review Exercises: Chapter 5 - Page 370: 52

Answer

10 holes long

Work Step by Step

The Pythagorean Theorem states: $$ a^2+b^2=c^2$$ Thus, we find: $$ l=\sqrt{8^2+6^2} \\ l=\sqrt{100} \\ =10$$
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