Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.8 Solving Applications - 5.8 Exercise Set - Page 362: 46



Work Step by Step

We are given the following equation: $$ h=48t-16t^2$$ Thus, plugging in $0$ for $h$ and looking for the solution besides t=0, we find: $$ 0=48t-16t^2 \\ t_{1,\:2}=\frac{-48\pm \sqrt{48^2-4\left(-16\right)0}}{2\left(-16\right)} \\ t=3$$
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