Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.8 Solving Applications - 5.8 Exercise Set - Page 362: 43

Answer

20

Work Step by Step

We are given the following equation: $$ h=48t-16t^2$$ Thus, plugging in $\frac{1}{2}$ for $t$, we find: $$ h=48\left(\frac{1}{2}\right)-16\left(\frac{1}{2}\right)^2 \\ h=24-4 \\ h=20$$
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