Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.8 Solving Applications - 5.8 Exercise Set - Page 362: 44



Work Step by Step

We are given the following equation: $$ h=48t-16t^2$$ Thus, plugging in $2.5$ for $t$, we find: $$h=48\left(2.5\right)-16\left(2.5\right)^2 \\ h=120-100 \\ h=20$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.