Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.8 Solving Applications - 5.8 Exercise Set - Page 362: 44

Answer

h=20

Work Step by Step

We are given the following equation: $$ h=48t-16t^2$$ Thus, plugging in $2.5$ for $t$, we find: $$h=48\left(2.5\right)-16\left(2.5\right)^2 \\ h=120-100 \\ h=20$$
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