Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 310: 55



Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ 2x^3-12x^2-x+6 ,$ is \begin{array}{l} (2x^3-12x^2)-(x-6) \\\\= 2x^2(x-6)-(x-6) \\\\= (x-6)(2x^2-1) .\end{array}
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