## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set: 50

#### Answer

$(4a-1)(2a^2+3)$

#### Work Step by Step

Using factoring by grouping, the factored form of the given expression, $8a^3-2a^2+12a-3 ,$ is \begin{array}{l} (8a^3-2a^2)+(12a-3) \\\\= 2a^2(4a-1)+3(4a-1) \\\\= (4a-1)(2a^2+3) .\end{array}

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