## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(3n-2)(3n^2+1)$
Using factoring by grouping, the factored form of the given expression, $9n^3-6n^2+3n-2 ,$ is \begin{array}{l} (9n^3-6n^2)+(3n-2) \\\\= 3n^2(3n-2)+(3n-2) \\\\= (3n-2)(3n^2+1) .\end{array}