Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - 5.1 Introduction to Factoring - 5.1 Exercise Set - Page 310: 47



Work Step by Step

Using factoring by grouping, the factored form of the given expression, $ 9n^3-6n^2+3n-2 ,$ is \begin{array}{l} (9n^3-6n^2)+(3n-2) \\\\= 3n^2(3n-2)+(3n-2) \\\\= (3n-2)(3n^2+1) .\end{array}
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