## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$-3t^3-t^2-t+6$
Removing the grouping symbols, then the given expression, $(7+t-5t^2+2t^3)-(1+2t-4t^2+5t^3)$, is equivalent to \begin{array}{l} 7+t-5t^2+2t^3-1-2t+4t^2-5t^3 .\end{array} By combining like terms, then \begin{array}{l} (2t^3-5t^3)+(-5t^2+4t^2)+(t-2t)+(7-1) \\\\= -3t^3-t^2-t+6 .\end{array}