Answer
$-3x^5+2x^3+\dfrac{3}{5}x^2-16$
Work Step by Step
Since the expression in parenthesis is preceded by a negative sign, then all terms inside the parenthesis will alter its sign when the parenthesis is removed. Hence, the given expression, $
-\left(3x^5-2x^3-\dfrac{3}{5}x^2+16\right)
$, is equivalent to
\begin{array}{l}
-3x^5+2x^3+\dfrac{3}{5}x^2-16
.\end{array}