## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$8a^3+8a^2+a-4$
Removing the grouping symbols, then the given expression, $(4a^2+a-7)-(3-8a^3-4a^2)$, is equivalent to \begin{array}{l} 4a^2+a-7+3+8a^3+4a^2 .\end{array} By combining like terms, then \begin{array}{l} 8a^3+(4a^2+4a^2)+a+(-7+3) \\\\= 8a^3+8a^2+a-4 .\end{array}