Answer
$r^{10}$
Work Step by Step
Using $a^x\cdot a^y=a^{x+y}$, then the given expression, $
r^3\cdot r^7\cdot r^0
$, simplifies to
\begin{array}{l}\require{cancel}
r^{3+7+0}
\\\\=
r^{10}
.\end{array}
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