Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 235: 23



Work Step by Step

Since $a^x\cdot a^y=a^{x+y}$, then the given expression, $ (5p)^0\cdot (5p)^{1} $, simplifies to \begin{array}{l}\require{cancel} (5p)^{0+1} \\\\= (5p)^{1} .\end{array} Since $(ab)^x=a^xb^x$, then the expression above simplifies to \begin{array}{l}\require{cancel} 5^1p^1 \\\\= 5p .\end{array}
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