Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 235: 20

Answer

$t^{16}$

Work Step by Step

Since $a^x\cdot a^y=a^{x+y}$, then the given expression, $ t^0\cdot t^{16} $, simplifies to \begin{array}{l}\require{cancel} t^{0+16} \\\\= t^{16} .\end{array}
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