Answer
The two lines are perpendicular to each other.
Work Step by Step
RECALL:
(1) The slope-intercept form of a line's equation is $y=mx+b$ where $m$= slope and $(0, b)$ is the line's y-intercept.
(2) Parallel lines have the same slope.
(3) Perpendicular lines have slopes whose product is $-1$ (negative reciprocals of each other).
Write each equation in slope-intercept form by solving for $y$ to obtain:
First Equation:
$y=-2x+5$
The slope of this line is $-2$.
Second Equation:
$2y-x=6
\\2y-x+x=6+x
\\2y=6+x
\\2y=x+6
\\\frac{2y}{2}=\frac{x+6}{2}
\\y=\frac{1}{2}x+3$
The slope of this line is $\frac{1}{2}$.
Note that $(-2)(\frac{1}{2})=-1$.
Thus, the two lines are perpendicular to each other.