#### Answer

Refer to the graph below.

#### Work Step by Step

Solve for $y$ by subtracting $1$ to both sides of the equation:
$y+1-1=6-1
\\y=5$
This means that the given equation is equivalent to, and has the same graph as, $y=5$.
RECALL:
The graph of a line whose equation is of the form $y=k$ where $k$ is a real number is a horizontal line whose y-intercept is $(0, k)$.
All points on the line have a y-coordinate of $k$.
Thus, the graph of the given equation is a horizontal line whose y-intercept is $(0, 5)$. All the points on the line have a y-coordinate of $5$.
The points $(-2, 5)$, $(0, 5)$, and $(2, 5)$ are all on the line.
Plot these three points and connect them using a line to complete the graph.
(Refer to the graph in the answer part above.)